Advances in Services Computing: 9th Asia-Pacific Services by Lina Yao, Xia Xie, Qingchen Zhang, Laurence T. Yang, Albert

By Lina Yao, Xia Xie, Qingchen Zhang, Laurence T. Yang, Albert Y. Zomaya, Hai Jin

This booklet constitutes the refereed court cases of the ninth Asia-Pacific providers Computing convention, APSCC 2015, held in Bangkok, Thailand, in December 2015.

The 17 revised complete papers and six brief papers provided have been conscientiously reviewed and chosen from quite a few submissions. The papers disguise quite a lot of issues in prone computing, net prone, cloud computing, safety in prone, and social, peer-to-peer, cellular, ubiquitous and pervasive computing.

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Additional info for Advances in Services Computing: 9th Asia-Pacific Services Computing Conference, APSCC 2015, Bangkok, Thailand, December 7-9, 2015, Proceedings

Example text

Case 2: Consider a positive minimal support set W = (w1 , y1 ), (w2 , y2 ), . . , (wl , yl ) of Φ such that (ui , xi ) ∈ U and (ui , xi ) ∈ W. Then there exists, at-least / W, otherwise W would not one (uj , xj ) ∈ U such that uj = ui and (uj , xj ) ∈ ¯j ) ∈ W, then this case would be similar to be a minimal support set. If (uj , x Case 1. We can conclude that uj does not belong to the proposition set of W. ¯j , the function Φ does not become Therefore, when we substitute any uj by x independent of ui , which again contradicts the fact that U is a strong minimal support set.

Ul , xl )} is said to be a support set of a service rule Φ defined over a set of Boolean propositions P = {p1 , p2 , . . , pn }, where xi ∈ {0, 1} and ui ∈ P ∀i = 1, 2, . . , l, if Φ evaluates to either 0 or 1, when u1 = x1 , u2 = x2 . . , ul = xl . Example 2. p8 ). {(p1 , 1), (p2 , 1), (p4 , 1), (p5 , 1)} is a support set of Φ, since Φ evaluates to 1 on the assignment p1 = 1, p2 = 1, p4 = 1, p5 = 1. A support set of a service rule Φ for which Φ evaluates to true is called a positive support set and a support set for which Φ evaluates to false is called a negative support set.

K, every neg¯i ), where ative (positive) minimal support set of Φ contains exactly one (ui , x (ui , xi ) ∈ U. Also no other positive (negative) minimal support set of Φ contains ¯i ) where (ui , xi ) ∈ U. any (ui , xi ) or (ui , x Proof. We present the proof for the positive minimal support set case and the proof for the negative minimal support set is similar. The proof is as follows: Since U = {(u1 , x1 ), (u2 , x2 ), . . , (uk , xk )} is a strong positive minimal support set of Φ, Φui =¯xi is independent of {u1 , u2 , .

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